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Physics 21 Online
OpenStudy (anonymous):

The potential in a region between x = 0 and x = 6.00 m is V = a + bx, where a = 13.2 V and b = -5.10 V/m. Determine the magnitude and direction of the electric field at x = 0, x= 3.0m and x=6.0m

OpenStudy (souvik):

\(E\)=-\(\frac{ dV }{ dx }\) and the direction of E is in +ve x direction..

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