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Find the value of X: x^-2=1/16 A. 4 and -4 B. only 4 C. 16 and -16 D. only 16
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\[1/4^2=1/16\]
\[\huge x^-2=\frac{1}{16} \rightarrow \frac{1}{x^2}=\frac{1}{16}\] \[\huge \rightarrow \frac{1}{x^2}=\frac{1}{4^2} \rightarrow \frac{1}{x}=\frac{1}{4}\] By invertendo x= 4
you can use ^{ -2} as an exponent of -2.
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