help.

Question

help.

anonymous · Answer

attachment

anonymous · Answer

We use d = rt: 

d = (8mi / hr)(3/4 hr) 

= 6 mi 

After she trains, we have 

6 = r(38/60 hr), so 

r = 9.47 mi / hr

anonymous · Answer

number 36 and 39.

ganeshie8 · Answer

to find the asymptotes, 
set the denominator equal to 0 and solve

ganeshie8 · Answer

$\large y = \frac{1}{x+2}$

ganeshie8 · Answer

set the denominator equal to 0 :

$\large  x + 2 = 0$

$\large x = -2$

ganeshie8 · Answer

so,  $\large  x = -2$ is an asymptote

ganeshie8 · Answer

u can use below to see how the graph looks like : https://www.desmos.com/calculator

anonymous · Answer

thats for vertical asymptote
theres horizontal also

anonymous · Answer

is 39 x = 2?

ganeshie8 · Answer

how did u get x  = 2 ?

anonymous · Answer

is it wrong?

ganeshie8 · Answer

$\large   f(x) =  \frac{3}{x-5} -1$

ganeshie8 · Answer

set the denominator equal to 0 and solve x

ganeshie8 · Answer

$\large x - 5 = 0$

$\large x  =   ?$

anonymous · Answer

x = 5

ganeshie8 · Answer

yes, 
wat about horizontal asymptotes ?

anonymous · Answer

idk she said that.

ranga · Answer

Vertical asymptotes are found by setting the denominator to zero and solving for x.
Horizontal asymptotes are found by finding the limit as x->infinity

ganeshie8 · Answer

^^

ganeshie8 · Answer

use below for horizontal asymptotes :
1) if the degree of numerator is less than denominators, then $y=0$ is the horizontal asymptote

ganeshie8 · Answer

its a trivial/boring asymptote, but nevertheless u need it for sketching the graph by hand