Question

What are the dimensions of a rectangle that has a perimeter of 56 units and an area of 96 square units?


a.

4 by 24

c.

14 by 14


b.

2 by 48

d.

3 by 32

Answer 1

suppose the dimensions of the rectangle are
length l and width w

perimeter = 2l + 2w
area = l*w

thus
2l + 2w = 56
l*w = 96

we have a system of two equations, can you solve it ?

Answer 2

a.

4 by 24

c.

14 by 14


b.

2 by 48

d.

3 by 32