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2ex^2-5xe^x=3e^x
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\[2ex^2-5xe^x=3e^x\]
Are you solving for x?
Yes
I would suggest to hit both sides with the natural log (I mean ln by "natural log" )
\(\Large\color{blue}{ \bf 2ex^2-5xe^x=3e^x }\) \(\Large\color{blue}{ \bf ln(2ex^2-5xe^x)=ln(3e^x) }\)
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Oh okay, so I would get x=-1?
Just checking to make sure I had the steps set up right.
You are telling me the answer, and saying that you are checking if you got the steps right? Please post what you did if you want me to check your work.
Okay one sec let me type it. Might take a moment :p .
|dw:1396823387373:dw|
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