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i need some help with some homework, first time i am doing probability and statistics, id like to know if my 2 answers below are correct, and how i can solve the remaining 2. There are 30 balls in a bucket: 10 green 12 red 8 blue **3 Balls are pulled up from the bucket.** a) What is the probability of all 3 being blue. $$ \frac{8}{30} * \frac{7}{29} * \frac{6}{28} = \frac{2}{145} $$ c) What is the probability of all 3 balls being different colors. $$ \frac{10}{30} * \frac{8}{29} * \frac{12}{28} = \frac{8}{203} $$ d) What is the probability of atleast 2 balls being green e) What i
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