Question

Proberbility homework help!

There are 30 balls in a bucket:

10 green

12 red

8 blue

3 Balls are pulled up from the bucket.

a) What is the probability of all 3 being blue.
8/30 * 7/29 * 6/28 = 2/145 correct or?

c) What is the probability of all 3 balls being different colors.
10/30 * 8/29 * 12/28 = 8/203, correct?

d) What is the probability of atleast 2 balls being green
Dont know how to solve this one.

e) What is the probability of 1 blue ball max.
Dont know how to solve this one.

Answer 1

a and b are correct, to solve c you can repeatedly apply the same logic as the first ones. at least 2 balls being green means there's 2 or more green balls, so the different combinations are {G,G,R},{G,R,G},{G,G,B},{G,B,G},{G,G,G}

Answer 2

so, 10/30 * 9/29 = 3/29 or ?

Answer 3

sorry I meant to solve d, c is ok