Question

Answer check por favor :)

Will take me a second to type -_-

Answer 1

\[e^2x-7e^x+12=0\]
\[(e^x)^2-7e^x+12\]
\[(e^x-3)(e^x-4)\]
\[u=e^x\]
(u-3)(u-4)=0
u=3, u=4
\[e^x=3, e^x=4\]
\[\ln (e^x)=\ln 3 \] x=ln3
\[\ln (e^x)=\ln 4\] x=ln4