Question

The length of a rectangle is one less than twice its width. If its perimeter is 34", what are the dimensions?

Answer 1

P = 2L + 2W

P = 34
L = 2W - 1

now we sub
34 = 2(2W - 1) + 2W
34 = 4W - 2 + 2W
34 + 2 = 4W + 2W
36 = 6W
6 = W
now sub 6 in for W in either equation to find L
L = 2W - 1
L = 2(6) - 1
L = 12 - 1
L = 11

check...
P = 2W + 2L
34 = 2(6) + 2(11)
34 = 12 + 22
34 = 34 (correct)

solution : W = 6 and L = 11

Answer 2

any questions ?

Answer 3

No I understand. Thank you

Answer 4

YW :)