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Calculus1
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http://apcentral.collegeboard.com/apc/public/repository/ap10_calculus_bc_scoring_guidelines.pdf #3 part C, how do you find t?
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just after a quick read... it the tangent is zero then the slope is zero... so the 1st derivative is zero... so find the value of t that makes the 1st derivative zero... so you are looking for a stationary point... i.e. a max, min or horizontal point of inflexion
So i should try to graph it on the calculator? and then pick one of those points?
well for mine they have used the chain rule to find dy/dx and since 2t - 4 can't be zero... you can ignore othe than \[t \neq 2\] so solve the numerator \[t e^{t -3} - 1 = 0\]
ya that is correct solve the numerator
t is not = 2
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