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a sporting good store received an order of 80 baseball caps, of which 12 were green. if 1 of the 80 caps is selected at random, what is the probability it will not be green?
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Alright so all together...we have 80 caps... 12 of which are green....so that is \[\large \frac{12}{80} = \text{green}\] So the probability that they will NOT be green...will be \[\large 1 - \frac{12}{80} = \frac{68}{80}\] And that can be simplified down a bit
so 85%?
Correct :)
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