Question

Solve on the interval : [0,2pi):

2cscx-3=-5

Answer 1

isolate csc x using basic algebra
\[\csc x = -1\]
now csc is the reciprocal of sin, or 1/sin
\[\frac{1}{\sin x} = -1\]
isolating sin x
\[\sin x = -1\]
from the unit circle you find that sin x = -1 at an angle of 3pi/2

\[x = \frac{3 \pi}{2}\]

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