Question

Find all solutions for (tan^2 θ − 16)(2 cos θ + 1) = 0

Answer 1

well the solutions are where

\[\tan^2(\theta) - 16 = 0\]

and

\[2\cos(\theta) + 1 = 0\]

hope it helps

Answer 2

oh wow I kept thinking I had to substitute them within the equation and then factor. I'm an idiot, thanks.