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OpenStudy (anonymous):
If a cylinder’s radius and height are each shrunk down to a third of the original size, what would be the formula to find the modified surface area?
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OpenStudy (anonymous):
Help any1??
OpenStudy (anonymous):
No???
OpenStudy (wwhitlock):
looks like math
OpenStudy (anonymous):
It is math. Areas are proportional to the square of the dimensions. Shrinking them by 1/3 cuts the area by (1/3) squared = 1/9. Area = 2 pi R h + 2 pi R^2
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