Question

A 100 kg granite rock has been sitting in direct sunlight for 3 hours. It has absorbed 4.5x10^5 calories through its exposure to the sun. If it is now at a temp. of 50 Celsius, what was its temp. initially? (stone(granite) Specific heat in calories per gram degC is 0.19

Answer 1

I got 26 degC ??

Answer 2

The relevant equation is:\[Q=mc DeltaT=mc \left( T _{2} -T _{1}\right)\]where Q is heat; m is mass; c is specific heat capacity; T2 is the final temperature; and T1 is the original temperature. Be careful with units.