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(x)= -x^2-3x+6 find the vertex, axis of symmetry, max or min value, range, interval increasing and decreasing, solve the equation f(x)=0
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To find the vertex, put the equation in vertex form by completing the square.
The vertex form of a parabola is: y = a(x - h)^2 + k where (h,k) is the vertex. So to find the vertex of y = -x^2-3x+6, put it in vertex form by completing the square.
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