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OpenStudy (anonymous):
Please help with Pre Calc!! Graph: (theta) = pi/4, r < 2
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OpenStudy (anonymous):
|dw:1396998101745:dw|
OpenStudy (anonymous):
what topic is this
OpenStudy (anonymous):
Polar coordinates/equations
OpenStudy (anonymous):
I actually think I have it now. Cuz (theta) = pi/4 would be in the first quadrant, and then with r less than 2, it would be an open circle at 2, being the first graph
OpenStudy (anonymous):
ohh i was gonna ask you what those were cuz they looked like points... unclear
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OpenStudy (anonymous):
ok well i tried to help! were these the only choices?
OpenStudy (anonymous):
yeah sorry my drawings didnt turn out too well.
OpenStudy (anonymous):
haha itts fine. glad you got it
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