Solve the problem as an inequality. A parallelogram has a base of 15 and an area which is less than or equal to 45. What is its height? A. x is less than or equal to 5 B. x is greater than or equal to 5 C. x is less than or equal to 3 D. x is greater than or equal to 3
so 15h is less than or equal to forty-five?
Yes
if you treat the inequality like an equation, you can solve it. if you divide by a negative number, you flip the inequality sign. if you divide by a positive number, you keep the same sign. So, I could have -3x is less than or equal to 15. I can treat it like -3x=15. divide both sides by -3, and x=5. now, since we divided by a negative number, we flip the sign from a less than or equal to sign to a greater than or equal to sign. but if it was 3x is less than or equal to 15, i would do the same process, but keep the original sign: less than or equal to. is that making sense?
yes it makes sense but just to make sure the correct answer is x<5
but greater than or equal to or less than an equal to?
still les than or equal to because you divided by a positive number. understand?
yes so the answer would be A
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