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give tan(theta) =4/3 and sin(-4/5) find cos(theta) 1/3 -1/3 3/5 -3/5 -sqrt3/5
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hint : \(\large \tan \theta = \frac{\sin \theta}{\cos \theta} \)
4/3*-4/5=cosθ
i got 8/15? but i know thats wrong
i got 8/15 wheni tried harsh123 solution and i got no solution for gabeshie8 solution
*ganeshie8
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\(\large \tan \theta = \frac{\sin \theta}{\cos \theta}\) \(\large \frac{4}{3} = \frac{\frac{-4}{5}}{\cos \theta}\) cross multiply \(\large 4 \cos \theta= 3\times \frac{-4}{5}\) divide 4 both sides \(\large \cos \theta= \frac{-3}{5}\)
oh thankyou
np :)
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