Question

What is the vertex of f(x) = x2 + 10x + 16?
A. (2, 6)
B. (1, 5)
C. (5, 9)
D. (-5, -9)
Find the vertex of the parabola formed by the following quadratic function: y = -3x2 + 12x - 7
A. (-2,-43)
B. (2, 5)
C. (-1, -22)
D. (1, 2)

Answer 1

\(\bf \textit{vertex of a parabola}\\ \quad \\
y = {\color{red}{ a}}x^2+{\color{blue}{ b}}x+{\color{green}{ c}}\qquad \quad
\left(-\cfrac{{\color{blue}{ b}}}{2{\color{red}{ a}}}\quad ,\quad {\color{green}{ c}}-\cfrac{{\color{blue}{ b}}^2}{4{\color{red}{ a}}}\right)\)

Answer 2

I KNOW THE FIRST ONE IS C

Answer 3

\(\bf f(x) = {\color{red}{ 1}}x^2 {\color{blue}{ +10}}x {\color{green}{ +16}}\qquad \qquad
y = {\color{red}{ -3}}x^2 {\color{blue}{ +12}}x {\color{green}{ -7}}\)

Answer 4

i got B @jdoe0001

Answer 5

yeap