Solve 3x^2 + 2x + 7 = 0. Round to the nearest Hundredth.

x ~ -1.90 & x ~ 1.23
x ~ -1.23 & x ~ 1.90
x ~ - 0.44 & x ~-3.56
No real solutions

Question

Solve 3x^2 + 2x + 7 = 0. Round to the nearest Hundredth. 

x ~ -1.90 & x ~ 1.23
x ~ -1.23 & x ~ 1.90
x ~ - 0.44 & x ~-3.56
No real solutions

luigi0210 · Answer

Use the quadratic formula.

anonymous · Answer

I did i came up with -1.8 and 1.20

luigi0210 · Answer

You sure you did it right?

anonymous · Answer

I really dont know i just got that though? Ugh!

anonymous · Answer

luigi0210 · Answer

Do the discriminate first $b^2-4ac$, it will tell you if the solution is real or not.

anonymous · Answer

A: 3
B:2 
C: 7
Right?

luigi0210 · Answer

Yup, now plug them in

anonymous · Answer

-80?
(2)^2 - 4(3)(7)
4 - 84
-80

luigi0210 · Answer

Yes, and negative means there are no real solutions..

anonymous · Answer

So it is no real Solution. Hahaha Thank you so much :P

luigi0210 · Answer

You're welcome :)