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A circle has its center at the center of a square with 6-inch sides. Find the area of the square not covered by the circle. Round the answer to the nearest tenth. http://media.education2020.com/evresources/647-07-03-00-00_files/i0060000.jpg
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Area of the square: \[A=s^{2}\]\[A=6^{2}\]\[A=36\] Area of the circle: \[A=\pi r^{2}\]\[A=\pi 3^{2}\]\[A=28.274\] Difference of the areas: A=A1-A2\]\[A=36-28.274\]\[A=7.7256\]
a. 29π cm c. 58 cm b. 29 cm d. 58 cm2
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