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Find the area of a circle with an area of pi(16^2 + 24x + 9)
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"Find the \(\bf area\) of a circle with an \(\bf area\) of pi(16^2 + 24x + 9)" ^ found, is right here
Huh?
16x+9?
@jdoe0001
well, the area is already a given it seems
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Sorry haha, I didn't realize what I wrote
Let me rephrase it
Find the radius of a circle with an area of \[\pi(16^2+24x+9)\]
@jdoe0001
\(\bf {\color{blue}{ \textit{area of a circle}=\pi r^2}} \\ \quad \\ \quad \\ Area=\pi(16^2+24x+9)\implies {\color{blue}{ \pi r^2}}=\pi(16^2+24x+9)\) solve for "r", the value would end up in terms of "x"
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