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Mathematics 10 Online
OpenStudy (anonymous):

what is the derivative of y=cosxcotx ?

OpenStudy (anonymous):

product rule

OpenStudy (anonymous):

Product rule is correct... U = cosx U' = -sinx V = cotx V' = -csc^2x y = UV y' = UV' + U'V

OpenStudy (anonymous):

thank you very much :)

OpenStudy (anonymous):

You are welcome..

OpenStudy (anonymous):

but can I please know what you have as your answer? just to know if I got it right please?

OpenStudy (anonymous):

-cosx (csc^2x +1)

OpenStudy (anonymous):

how did you get that? :o

OpenStudy (anonymous):

well I re-wrote my answer

OpenStudy (anonymous):

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