Question

(calculus) Can someone explain why x=3 is neither a relative max or min?...

Answer 1

http://apcentral.collegeboard.com/apc/public/repository/ap10_calculus_ab_scoring_guidelines.pdf

Answer 2

Question 5, part c

Answer 3

Question 5 asks find the x-coordinate of each critical point of h(x)=g(x)-(1/2)x^2 and they give the graph of g'(x).
I found the critical points x=sqrt 2 and x=3.
But the answer says h(x) has neither a max or min at x=3.