Question

Transforming functions.

Answer 1

@ganeshie8

Answer 2

Is a function a quadratic equation?

Answer 3

to shift left by 6 units,
just replace "x" by "x+6" everywhere

Answer 4

so that eliminates a and c

Answer 5

replace "x" by "x+6" in the given equation and see what u get ?

Answer 6

x+6-3 and 4(x+6)

Answer 7

given function :

\(\large \mathbb
f(x) = \left\{
\begin{array}{lr}
x-3 & : x \le 0\\
4x & : x \gt 0
\end{array}
\right.

\)

Answer 8

to shift it to left by "6" units,
replace "x" by "x+6"


function after shifting left by 6 units :

\(\large \mathbb
f(x) = \left\{
\begin{array}{lr}
x+6-3 & : x+6 \le 0\\
4(x+6) & : x+6 \gt 0
\end{array}
\right.

\)

Answer 9

simplify

Answer 10

x-3
4x+24

Answer 11

simplifying gives u :

\(\large \mathbb
f(x) = \left\{
\begin{array}{lr}
x+3 & : x\le -6\\
4(x+6) & : x6 \gt -6
\end{array}
\right.

\)

Answer 12

*facepalm*

Answer 13

:)

Answer 14

So would it be B then?

Answer 15

B is correct !

Answer 16

remember below transformations :

shift left by "k" units : x -> x+k
shift right by "k" units : x -> x-k