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Trigonometry Question: Solve the equation for θ if 0° ≤ θ < 360°. (Enter your answers as a comma-separated list.) square root (2) sec theta = 2 sec theta = 2/(square root (2)) sec theta = 2(sqrt(2))/2 **2(sqrt(2))/2 isn't on the table I've been using. http://mathmistakes.info/facts/TrigFacts/learn/vals/sum.html Where do I go from here?
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take reciprocal sec = 1/cos \[\sec \theta = \frac{2}{\sqrt{2}} \leftarrow \rightarrow \cos \theta = \frac{\sqrt{2}}{2}\]
Oh... Thanks! :)
yw :)
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