Question

Algebra 2

Answer 1

we have to find the LCD, then write in equivalent fractions, and then add it.
Btw im in the Rational Functions unit

Answer 2

factor out the denominator of the first fraction. Do you now see the LCD ?

Answer 3

For connections?

Answer 4

not for connections

Answer 5

\[\frac{6x+1}{x^2-9}+\frac{4}{x-3}\]
\[\frac{6x+1}{(x+3)(x-3)}+\frac{4}{x-3}\]
\[\frac{6x+1}{(x+3)(x-3)}+\frac{4(x+3)}{(x+3)(x-3)}\] is a start

Answer 6

then add up in the numerator and you are done

Answer 7

well not quite done, you still have to multiply out and combine like terms
\[\frac{6x+1+4(x+3)}{(x+3)(x-3)}\]
\[\frac{6x+1+4x+12}{(x+3)(x-3)}\]
\[\frac{10x+13}{(x+3)(x-3)}\]

Answer 8

can u guys help me with more?

Answer 9

sure go ahead and post

Answer 10

i only have like 4 more, it'll take awhile to put up

Answer 11

my handwriting sucks sorry lol