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How do i claculate the area inside the six leaved rose r^2=2sin 3theta
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did you find the intersection?
nope
ok, then do so
i think intersection is o
0 = 2 sin(3 theta)
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3(theta)=0
no, the other one is 3theta = pi so theta = 0 or pi/3. That is the limit of integration you'll use
ok i understand .Thankx very much
@sourwing
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