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Use the quadratic formula to solve 2y2 + 6y – 8 = 0. A. {–4, –1} B. {4, –1} C. {–4, 1} D. {4, 1}
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2y^2 +8y-2y-8=0 now you can solve
a, b, c, d which one is it
what is the quadratic eq?
2y^2 + 6y – 8 = 0
sorry, I mean what is the quadratic formula? I assume that is what you are supposed to use based on the question
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The answer is C
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