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MIT 18.01 Single Variable Calculus (OCW)
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OpenStudy (anonymous):
(In the form of 0*infinity) Find the limit as x approaches pi/2 from the negative of (pi/2-x)secx
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OpenStudy (phi):
write it as \[ \frac{ \frac{\pi}{2} - x}{\cos(x)} \] now it is in the form 0/0
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