Question

Need help with another calculus problem, posting below.

Answer 1

Same graph: http://i.imgur.com/1fUfmNm.png
different part: http://i.imgur.com/pZvyQct.png

Answer 2

Why do you need help with this, exactly?

Answer 3

Don't really understand how i'm supposed to arrive at the integral expression, and it's practice problems from past ap exams that i have for hw..

Answer 4

V = ∫(area of cross section)

Answer 5

now it's the matter of finding the side length of the square

Answer 6

The area of each cross section is given by \(|h-g|^2\)

Answer 7

\[
15 = \int\limits_0^1(h-g)^2\;dx = \int\limits_0^1(kx(1-x)-3(x-1)\sqrt x)^2\;dx
\]

Answer 8

Oh..