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Mathematics 20 Online
OpenStudy (anonymous):

find dy/dx of tan^2(sin^3x)

OpenStudy (kainui):

What's your best attempt? You'll have to use the chain and power rules.

OpenStudy (anonymous):

I got ...6tan(sin^3x)sec^2(sin^3x)sin^2xcox

OpenStudy (anonymous):

cosx*

OpenStudy (kainui):

Looks right to me.

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