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proof for sin(90+x)
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sin(90+x)= sin90cosx + cos90sinx
\[\sin \left( x+y \right)=\sin x \cos y+\cos x \sin y\]
@narain: we don't "prove" sin (90+x ); we write out the expression using the sum identity for that expression. See surjithayer's identity, above. Please use that identity to simplify sin (90+x).
sin (90 + x) = cos [90 - (90 + x)] = cos (-x) = cos x|dw:1397149160666:dw|
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