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Mathematics 20 Online
OpenStudy (anonymous):

Please Solve over the interval [0,2pi) (√3-cotx)(2-cscx)=0

OpenStudy (anonymous):

(cotx=√3)->tanx=√3/3 (cscx=2)->sinx=1/2

OpenStudy (anonymous):

tanx is √3/3 in quadrants I &3 at pi/6

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