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OpenStudy (anonymous):
Please Solve over the interval [0,2pi) (√3-cotx)(2-cscx)=0
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OpenStudy (anonymous):
(cotx=√3)->tanx=√3/3 (cscx=2)->sinx=1/2
OpenStudy (anonymous):
tanx is √3/3 in quadrants I &3 at pi/6
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