Question

c^2-4c=0, what is the solutions to this equation?
0,-4
0,4(square rooted)
0,4
1,-4(square rooted)

Answer 1

are*

Answer 2

0,4

Answer 3

How is it that :3

Answer 4

\[\huge c^2-4c=0 \rightarrow c(c-4)=0\]
\[\huge c= 0 ---or ---(c-4)=0\]
c=0 or c= 4
Hence 0, 4 are the required answers

Answer 5

Gotcha, thanks. I'm unsure because I didn't know how to do it with a binomial.