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What is the solution for x^2 + 4x = 96?
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Are the solutions***
rewrite the equation as \[x^2 + 4x - 96 = 0\] the quadratic can be solved by factoring... find the factors of -96 that add to 4 the larger factor is positive... then its (x + factor 1)(x + factor 2) = 0 hope it helps
The factors are 12 and 8?
Add to for though...
it***
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nearly... so its 12 and -8 so you have (x +12)(x -8) = 0 so if either binomial is zero, the equation is zero so you need to solve for x, the following x + 12 = 0 and x - 8 = 0 and then you'll have your solutions.
-12 and 8?
@campbell_st
thats correct
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