Find all solutions in the interval [0, 2π). sin2x + sin x = 0 Options: a. x = 0, π, 4π/3, 5π/3 b. x = 0, π, π/3, 2π/3 c. x = 0, π, 3π/2
@jdoe0001 Please help??
You already copy-pasted an answer from https://answers.yahoo.com/question/index?qid=20140124114101AAriB8J in your last question. Why not just use that?
BECAUSE THE ANSWER IS WRONG
If you were really google savvy, you'd use wolfram alpha here...
You're killing me here. If you don't want to help then go away.
I tried to help. You didn't appear willing to put in effort, then you copy-pasted someone else's answer from yahoo and made it seem like it was your own. I even gave you a place (wolfram alpha) that would give the answer!
btw @girlfromafrica none of the above answer choices are correct.
But those are the only options given. @agent0smith
look here and you'll see none match those options. There's a typo in the choices i guess. http://www.wolframalpha.com/input/?i=solutions+of+sin2x+%2B+sin+x+%3D+0+in+the+interval+%5B0%2C+2pi%29
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