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how many roots does 2x^2-7x-5=0 have ?
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The discriminant \(\Delta = b^2 - 4ac\) from the quadratic formula \(x = \frac{-b \pm \sqrt{\Delta}}{2a}\)gives us this information. You can see that if delta is negative, there are no real solutions because we cannot take the square root of a negative number; if delta is zero we get one solution (sometimes called a double root) and if it is positive we get two solutions.
2 should be
\[ a = 2,\quad b = -7,\quad c = -5 \\ \Delta = (-7)^2 - 4(2)(-5) = 49 + 40 > 0 \] I agree with mohammad.arqum.
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