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Please VERIFY (cscx-1)(sinx+1)=cosxcotx
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I want to work the left side... (cscx-1)(sinx+1)= csc(x)sin(x)+csc(x)-sin(x)-1= 1+csc(x)-sin(x)-1= csc(x)-sin(x)= 1 / sin(x) - sin(x)= 1 / sin(x) - sin^2(x) / sin(x)= 1 - sin^2(x) / sin(x)= cos^2(x) / sin(x)= [ cos(x) / sin(x) ] * cos(x) = [ cot(x) ] * cos(x) = both sides are equal.
Wow that makes perfect sense. Thanks!
You welcome !
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