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please help!! log(2x+1)=1-logx
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I did part of it and got stumped...
log (2x+1) + log x = 1 log x(2x+1) = 1 x(2x+1) = 10
log(2x+1)=1-logx log(2x+1)=log10-logx log(2x+1)=log(10/x) 2x+1=10/x 2x^2+x=10 2x^2+x-10=0
Same thing as divu is getting...
2x^2+x-10=0 (2x+5)( x-2)=0
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Go , you got it from here !
Thank you Basil!
It's my pleasure :)
Any my first day on this website;)
And...
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Math wiz dude! :)
Thank you !
I'm just 14 though...
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