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Mathematics 15 Online
OpenStudy (anonymous):

Trouble understating a Telescope series part of question.

OpenStudy (anonymous):

\[\sum_{n =1} \frac{2}{n^2-1)}\]

OpenStudy (anonymous):

\[ n^2-1 = (n-1)(n+1) \]

OpenStudy (anonymous):

So, its a test for divergence what I did was 2/(n-1)(n+1) = 1/(n-1) - (1/n+1)

OpenStudy (anonymous):

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