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Bobby has a bond earning 11% yearly interest and another bond worth 3 times as much earning 10% simple interest. If the total yearly interest is $307.50, find the value of each bond.
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these are my choices. 600,1800 - 750,2250 - 900,2700 - 1050, 3150 - or none of these.
Use algebra.
what formula?
simple interest\[ I = Prn \]compound interest \[ I = Pr^n \]Since there is only one year, \(n=1\).
Anyway, let one of the bonds be values at \(x\) and the other valued at \(3x\).
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\[ 0.11x + 0.10(3x) = 307.50 \]
x= 750 so 3x = 2250
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