Question

-cos squar(theta)/sin squar(theta)

Answer 1

\[-\dfrac{\cos^2\theta}{\sin^2\theta} = -\left(\dfrac{\cos\theta}{\sin\theta}\right)^2\]

Answer 2

What is \(\dfrac{\cos\theta}{\sin\theta}\)?

Answer 3

Or to help you, what is \(\dfrac{\sin\theta}{\cos\theta}\)?