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sin(3x)=-0.7843
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\[0 degrees \le x <360 degrees\]
Find 3x first
i took the inverse sin of -.07843=-51.655 not exactly sure wat to do next
If sin(3x)=-0.7843, what's the general formula for the value of 3x?
not sure
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What's the period of sine?
Other than that, the formula \(\sin(180^\circ-x)=\sin x\) may help you.
sin(3x) = -0.7843 arcsin( sin(3x) ) = arcsin( -0.7843 ) 3x = arcsin( -0.7843 ) x = 1/3 arcsin( -0.7843 )
you found arcsin(-0.7843) = -51.655° to get x, just divide this number by three
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