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Mathematics 14 Online
OpenStudy (anonymous):

Integral coming up right away!

OpenStudy (anonymous):

\[\int_0^{\pi/3}\dfrac{1}{1-\sin x} dx\]

OpenStudy (anonymous):

Ok so I think it's got to do with that identity of int f(a - x) = int f(x)

OpenStudy (anonymous):

So sin(pi/3 - x) = 2 sin(x)

OpenStudy (anonymous):

|dw:1397395203006:dw| substitute this and check for once.

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