Question

Find all roots of 4x^2-7x+3

Answer 1

\[\frac{ -b^2\pm \sqrt{b^2-4ac} }{ 2a }\]
where \( ax^2+bx+c=0 \)

Answer 2

I come up with
(4x+3)(1x-1)
4x-3=0, x=3/4
3x-3=0 x =-1

Doe those answers look correct?

Answer 3

no, i assume you mixed up a sign somewhere

Answer 4

Last one should have been x-1=0 so x=1