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OpenStudy (hoblos):
|dw:1397407723241:dw|
cos = adjacent / hypotenuse
for angle B , AB is the adjacent, and BC is the hypo
so we have cos45 = AB/BC
can you calculate BC now ?
OpenStudy (anonymous):
what is M? this is a 45 45 90 triangle, as such the ratios are x,x, Root2(x) .
thus the answer would be 19*sqrt(2)
OpenStudy (anonymous):
so it would be this->0.70710678118 * 19 right?
OpenStudy (hoblos):
if cos45 = AB/BC
then BC= AB/cos45 = 19/0.70710678118
OpenStudy (anonymous):
oh okay.
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OpenStudy (hoblos):
then what would be the answer ?
OpenStudy (anonymous):
13.435028842420001? so about 13?
OpenStudy (hoblos):
|dw:1397408313528:dw|
OpenStudy (anonymous):
:/. heh..... i'm not good at these.
OpenStudy (anonymous):
plus super tired today. not helping with concentration.
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OpenStudy (anonymous):
you don't divide you have to multiply by sqrt(2)
OpenStudy (hoblos):
\[\cos 45 = AB \div BC \] \[BC = AB \div \cos45 \] \[BC = 19 \div 0.70710678118 = ?\]
OpenStudy (anonymous):
=26.9
OpenStudy (hoblos):
correct
OpenStudy (anonymous):
thats wrong hoblos
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OpenStudy (anonymous):
why?
OpenStudy (anonymous):
BC= cos(45) TIMES AB
OpenStudy (anonymous):
when you do algebra, to simplify an equation with divisions, you must multiply both sides.
OpenStudy (anonymous):
so BC=0.70710678118*19?
OpenStudy (anonymous):
oh wait, im sorry, we are doing different things
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OpenStudy (anonymous):
my apologies, he is using the angular values, I was using a known ration for 45,45,90 triangles.
OpenStudy (hoblos):
yeah you were using another method, but both have same answers surely.
OpenStudy (anonymous):
. .
-
OpenStudy (anonymous):
sooo.. still the same answer?
OpenStudy (hoblos):
don't be confused @waddlederp
you found the right answer, it's 26.9
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