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Calculus rotation problems
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Suppose that the function f has a continuous second derivative for all x, and that f(0)=2 f'(0)=-3 and f"(0)=0. Let g be a function whose derivative is given by\[g'(x)=e ^{-2x}(3f(x)+2f'(x))\] for all x.
a) write an equation of the line tangent to the graph of f the the point where x=0
Im lost I have no clue where to start
recall the tangent line at x=0 is y-f(0)=f'(0)(x-0)
just like the tangnet line at x=a to y=f(x) is y-f(a)=f'(a)(x-a)
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