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Help Pwease!! Write the first three terms of the binomial expansion, expressing the result in simplified form. (x^2+2)^14
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expansion: (n) a^i b^n-i (i)
(n) (i) is n! / (i! n-i !)
i! is i*i-1*i-2*i-3... for instance, 3! = 3*2*1=6
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